• Ephera@lemmy.ml
    link
    fedilink
    English
    arrow-up
    0
    ·
    2 days ago

    You know, after posting that comment, I really doubted myself, if it really is binary search, because Wikipedia also tells me it needs to be a sorted array.

    But yeah, I think that’s only relevant, if your method of checking whether it’s in one half or the other uses > and <. As far as I can tell, so long as you can individually identify the fuses, a.k.a. they’re countable, then you can apply binary search.

    • lunarul@lemmy.world
      link
      fedilink
      arrow-up
      0
      ·
      2 days ago

      If when you divide your set in two, you can reliably tell which of the two subsets definitely has what you’re looking for, then it’s binary search.